**Answer: We have**

First term = 2

Let *d* be the common difference of the A.P.

Therefore, the A.P. is 2, 2 + *d*, 2 + 2*d*, 2 + 3*d*, …

Sum of first five terms = 10 + 10*d*

Sum of next five terms = 10 + 35*d*

According to the given condition,

=>10+10d = 1/4(10+35d)

=>40+40d = 10+35d

=>30 = −5d

=>d = −6

∴ a_{20} = a+(20−1)d = 2+(19)(−6) = 2−114 = −112

**Hence, the 20th term of the A.P. is –112.**